IGCSE Additional Mathematics (0606)
Solving trigonometric equations
What this topic tests, the mistakes that cost marks, and one exam-style question worked through step by step.
Key ideas and common mistakes
- When solving a trigonometric equation set as a product equal to zero, solve each factor separately and check that all solutions fall within the specified interval.Common mistake: Students often miss solutions by not considering both factors or by ignoring the domain.
- When solving trigonometric equations like cos y = 1/2 over a full cycle, the student must find all solutions in the specified interval by considering all quadrants where the function is positive or negative, not just the basic angle.
- When solving trigonometric equations over a given interval, you must first convert the interval for x to the corresponding interval for the argument (here, x/6), or else you may include extraneous solutions outside the original range.
- When solving trigonometric equations involving tan(kx), factorise instead of dividing by tan(kx) to avoid losing solutions where tan(kx) = 0, and adjust the interval for kx to capture all solutions within the original x-range.
- When solving trigonometric equations by factoring, check all factors for solutions within the given interval, and reject impossible values (like sin x outside [−1, 1]).Common mistake: Missing endpoints or including extraneous roots are common errors.
- To solve a trigonometric equation involving sec² and tan, use the identity sec²(θ) = 1 + tan²(θ) to rewrite in terms of tan, factorise, and remember to double the solution range for 2x before halving to find x.Common mistake: A common mistake is to solve for x directly without adjusting the range for the multiple angle.
Worked example
Solve the equation (3 - 2 cot x) cos x = 0 for 0 < x ≤ pi/2.
Try it first, then show the working
-
Product is zero, so cos x = 0 or 3 - 2 cot x = 0.
-
cos x = 0 gives x = pi/2 (= 1.57) in the range 0 < x <= pi/2.
-
3 - 2 cot x = 0 gives cot x = 3/2, so tan x = 2/3.
-
x = arctan(2/3) = 0.5880 = 0.588 (3 s.f.), which lies in the range.
-
Solutions: x = 0.588 and x = pi/2.
Answer: x = 0.588 or x = pi/2 (1.57)
Try one yourself
Hence solve the equation cot y / (cosec y - 1) + cot y / (cosec y + 1) = 4 for 0 < y < 360 degrees.Answer it and get it marked →
Solve 5 cos(x/6) + 3 = 0 for -1080 degrees <= x <= 1080 degrees.Answer it and get it marked →
Solve tan^2(3x) - 9 tan(3x) = 0 for 0 degrees <= x <= 120 degrees.Answer it and get it marked →
16 exam-style questions on Solving trigonometric equations, each marked to the scheme.
More IGCSE Additional Mathematics topics
- Arc length and sector area (radians)12 questions
- Domain and range11 questions
- Laws of logarithms12 questions
- Arrangement and selection problems21 questions
- Transforming relationships to linear form10 questions
- nth term and sum of progressions13 questions
- Connected rates of change13 questions
Questions are exam-style practice written to the IGCSE Additional Mathematics (0606) syllabus. Cambridge IGCSE is a registered trademark of Cambridge University Press & Assessment; MOOBON Axiom is independent and not affiliated with it.