IGCSE Additional Mathematics (0606)

Solving trigonometric equations

What this topic tests, the mistakes that cost marks, and one exam-style question worked through step by step.

Key ideas and common mistakes

Worked example

Solve the equation (3 - 2 cot x) cos x = 0 for 0 < x ≤ pi/2.

Try it first, then show the working
  1. Product is zero, so cos x = 0 or 3 - 2 cot x = 0.
  2. cos x = 0 gives x = pi/2 (= 1.57) in the range 0 < x <= pi/2.
  3. 3 - 2 cot x = 0 gives cot x = 3/2, so tan x = 2/3.
  4. x = arctan(2/3) = 0.5880 = 0.588 (3 s.f.), which lies in the range.
  5. Solutions: x = 0.588 and x = pi/2.
Answer: x = 0.588 or x = pi/2 (1.57)

Try one yourself

16 exam-style questions on Solving trigonometric equations, each marked to the scheme.

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