IGCSE Additional Mathematics (0606)
nth term and sum of progressions
What this topic tests, the mistakes that cost marks, and one exam-style question worked through step by step.
Key ideas and common mistakes
- To find earlier terms in an arithmetic progression when a later term and the common difference are given, subtract multiples of the common difference from the known term.Common mistake: Students often add instead of subtracting or use the wrong multiple.
- When relating sums of different numbers of terms in an arithmetic progression, set up and solve an equation using the series sum formula for each case.Common mistake: Students often forget to use the correct n for each sum or misapply the formula.
- To relate the first term and common difference using a condition on sums of terms in an arithmetic progression, substitute the sum formula for each case and equate, being careful to expand and collect like terms for a and d before solving.Common mistake: A common error is to substitute values or not fully expand the sums, leading to incorrect coefficients.
- Recognize that ln of powers (e.g., ln 8 = 3 ln 2) rewrites the sequence as an arithmetic progression in multiples of ln 2, so the common difference is found using these multiples, not the original numbers.
- When summing a range of terms in a sequence, the number of terms is last minus first plus one (inclusive counting).Common mistake: Students often forget the '+1' and get one term too few.
- When solving for the smallest integer n where a sum exceeds a value, if the quadratic solution is not whole, you must round UP, since rounding down gives a sum just below the target.Common mistake: Students often mistakenly round down or take the integer part.
Worked example
Write down expressions for the 1st term and the 3rd term of this progression. Give each answer in terms of d only.
Try it first, then show the working
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Use the formula for the nth term of an arithmetic progression to express the 1st term in terms of d.a = 7 - 3d
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Correctly express both the 1st term and the 3rd term in terms of d: 1st term = 7 - 3d, 3rd term = 7 - d.1st term = 7 - 3d, 3rd term = 7 - d
Answer: 1st term = 7 - 3d, 3rd term = 7 - d
Try one yourself
Its first 5 terms add up to 61/27. Find the value of a.Answer it and get it marked →
Find the 71st term and the 90th term.Answer it and get it marked →
Find the common difference of the progression.Answer it and get it marked →
13 exam-style questions on nth term and sum of progressions, each marked to the scheme.
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Questions are exam-style practice written to the IGCSE Additional Mathematics (0606) syllabus. Cambridge IGCSE is a registered trademark of Cambridge University Press & Assessment; MOOBON Axiom is independent and not affiliated with it.