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SPM Additional Mathematics (KSSM)

Question
Bahasa Melayu
Rajah 4 menunjukkan sebahagian daripada lengkung $y = f(x)$, dengan keadaan $f(x) = -(x + 6)(x - 2)(x - 4)$, dan lengkung $PQR$, dengan keadaan $g(x) = -\frac{3}{4}(2x - 8)^2$. Kedua-dua lengkung itu bertemu paksi-$y$ pada titik $P$ dan bertemu paksi-$x$ pada titik $Q$.

Oleh sebab $P$ terletak pada paksi-$y$, koordinat-$x$ bagi $P$ ialah $0$. Cari koordinat-$y$ bagi $P$.

English
Diagram 4 shows part of the curve $y = f(x)$, where $f(x) = -(x + 6)(x - 2)(x - 4)$, and the curve $PQR$, where $g(x) = -\frac{3}{4}(2x - 8)^2$. Both curves meet the $y$-axis at point $P$ and meet the $x$-axis at point $Q$.

Since $P$ lies on the $y$-axis, its $x$-coordinate is $0$. Find the $y$-coordinate of $P$.
OPQRy = f(x)y = g(x)xy
[2 marks]
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Modelled on SBP trial · Kertas 2 · Q10(a)

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Modelled on SBP trial · Kertas 2 · Q10(a)

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